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in an examination 95%of the candidates passed and 92 failed find the number of candidates who appeared for the examination
Posted by Shahista Anjum 7 years, 2 months ago
- 2 answers
Naveen Sharma 7 years, 2 months ago
Ans. Let Number of Candidate = y
Pass % = 95%
So Fail % = 100-95 = 5%
Number of Failed Candidate = 92
Then
\({y \times 5 \over 100} = 92\)
=> \(y = {92 \times 100 \over 5 } = 1840\)
No of Total Candidate = 1840
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Manish Gandhi 7 years, 2 months ago
Let the Total Candidates are x.
Total Pass Candidates = 95%
Remaining = 100% - 95% = 5% => 5% candidates failed which is equal to 92 (given)
=> 5% of x = 92 => x = 92 * 100/5 => 92 * 20 => 1840 (Answer)
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