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How many words with or without meaning can be formed from the letters of the word hcverma when 1) at least three consonants occupy the odd placed

Posted by Vivek Kumar 7 years, 2 months ago

CBSE > Class 11 > Mathematics

1 answers

Manish Gandhi 7 years, 2 months ago

Total arrangements possible are 7P7 = 7! = 5040

There are 2 vowels & 5 cosonants => there is only one way when the given condition will not meet & that is when both these vowels will occupy the odd places. Now, the no. of ways it is possible = 4P2 * 5P5 = 12 * 120 = 1440

=> Total words which can be formed in the required fashion are 5040-1440 = 3600 (Answer)

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