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Weight of an empty glass is …

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Weight of an empty glass is 1N. When it is completely filled with water the weight observed is 4N. If you throw the water and fill the empty glass partly with sand and its weight becomes 4N, if the rest of glass is now filled up with water, the weight becomes 6N, what is relative density of sand?

Posted by Harsh Jain 7 years, 2 months ago

CBSE > Class 09 > Science

1 answers

Shweta Gulati 7 years, 2 months ago

Weight of empty glass = 1N

Weight of water alone = 4N-1N= 3N

Weight = mg

Mass of water = 3/9.8 = 0.306 kg

Density of water = 1000kg/m³

Volume of glass = 0.306/1000 = 3.06 X 10^-4 m³

Weight of half glass sand = 4N-1N =3N

Weight of full glass sand = 3N+3N = 6N

Mass of full glass sand= 6N/9.8 = 0.612kg

Density of sand = Mass of sand/Volume of glass = 0.612/(3.06 X 10^-4) = 2000kg/m³

Relative density of sand = Density of sand/Density of water

= 2000/1000 =2

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