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Ask QuestionPosted by Lucky Yadav 3 years, 7 months ago
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Posted by Ankit Kumar 3 years, 9 months ago
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Yogita Ingle 3 years, 9 months ago
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
Posted by Shivam Yadav 3 years, 9 months ago
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Gulshan Boss Gm Mahto 2 years, 10 months ago
Posted by Rahul Jaykar 4 years, 1 month ago
- 2 answers
Rajan Kumar Pasi 3 years, 10 months ago
Ek Kamre Ki lambai 5 metre 4 metre aur unchai 3 metre kramank 74 50 Prati metre per kidhar se is Kamre Ki diwaron per chhat par Safed karane ka Vyakhya kijiye
Sol: Pi ka maan 3.14 ya 22/7 hota hai.
Length = l = 5 m
Breadth = b = 4 m
Height = h = 3 m
Kamray ka prishthiya kshetrafal =
{tex}\huge {=> \ 2\times(l\times b + b\times h+l\times h)}\\
\huge {=> \ 2\times(5\times 4 + 4\times 3+5\times 3)}\\
\huge {=> \ 2\times(20 + 12+15)}\\
\huge {=> \ 2\times47}\\
\huge {=> \ 94 \ m^2}\\{/tex}
Chhat ka kshetrafal =
{tex}\huge {=> \ l\times b}\\
\huge {=> \ 5\times 4}\\
\huge {=> \ 20 \ m^2}\\{/tex}
Safed rang karne ka kul kshetrafal = 94 + 20 = 114 m2.
Safed rang karwane ka kul mulya ya kharcha = 114 x 74.50 Rs. = {tex}\Large {\boxed{8493 Rs.}}{/tex}
Ajeet Bainsla Gurjar 4 years, 1 month ago
Posted by Vivek Sharma 4 years, 1 month ago
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Posted by Himanshu Yadav 4 years, 2 months ago
- 2 answers
Posted by Royãl Goldy 4 years, 2 months ago
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Rajan Kumar Pasi 3 years, 10 months ago
Sol: Let the cost of a notebook = x Rs.
Let the cost of a pen = y Rs.
Thus, according to the question:
Cost of notebook = twice the cost of pen
x = 2 x y
Ans => {tex}\huge \boxed {x = 2y }{/tex}
Posted by Lakhan Singh 4 years, 3 months ago
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Posted by Aman Varya 4 years, 5 months ago
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Posted by Krishna Kaithwas 4 years, 5 months ago
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Posted by Lucky Chaudhary 4 years, 5 months ago
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Posted by Un Known 4 years, 5 months ago
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Rajan Kumar Pasi 3 years, 10 months ago
Sol: Let the no. of extra units = x
Thus,
{tex}\text {Let the original bill = y Rs.}\\ \text {Therefore, Original amount+ 20% fine = 28363.20}\\ \text {=> y + 20% of y = 28363.20}\\ \text {=> y + }{\frac{20}{100}}\times \text{ y = 28363.20}\\ \text {=> }{\frac{120}{100}}\times \text{ y = 28363.20}\\ \text {=> }{\frac{6}{5}}\times \text{ y = 28363.20}\\ \text {=> }\text{ y = }{28363.20\times {\frac{6}{5}}}\\ \text {=> y = }\boxed{23636 Rs.}\\ Now, {=> \ 1910 + 71\times x = 23636}\\ {=> \ 71\times x = 23636-1910}\\ {=> \ 71\times x = 21726}\\ {=> \ x = \frac{21726}{71}}\\ {=> \ x = \boxed{306}}\\{/tex}
So, the Former reading of the meter was = 4777 - 306 = {tex}\huge {\boxed{4471} \ units.} \\ All \ the\ best\ :-)...{/tex}
Posted by Md Zafar Husain 4 years, 6 months ago
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Posted by Sonubaisla Baisla 4 years, 6 months ago
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Posted by Dinesh Kanaujiya 4 years, 7 months ago
- 4 answers
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