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  • 2 answers

Abhishek Nanda 3 years, 11 months ago

X¹+X²+X³ Y¹+Y²+Y³ ------- ' ------- 3. 3

Sanjay Sangwan 3 years, 11 months ago

The point where the medians of three side intersect each other
  • 2 answers

Anurag Verma Student 3 years, 11 months ago

Heeloe

Vanshika Jasuja 3 years, 11 months ago

Nhi malum
  • 0 answers
  • 2 answers

[Vishal Kumar Paswan] [11] 3 years, 11 months ago

sin²A + sin²A*tan²A = sin²A(1+tan²A) = sin²A*sec²A = (sin²A)/(cos²A) = tan²A

Karamjitsidhu Karamjit Singh 3 years, 11 months ago

0
  • 2 answers

Anshul Vishwakarma 3 years, 11 months ago

1/8

Pavan Rajesh 3 years, 11 months ago

1/8
  • 1 answers

Anushka Tyagi 3 years, 11 months ago

Let x be the price of 1 pencil and y be the price of 1 pen, Now, According to the question  And   Now, The points (x,y), that satisfies the equation (1) are  X3-410Y5100 And, The points(x,y) that satisfies the equation (2) are  X38-2Y5-212 The Graph,  As we can see from the Graph, both line intersects at point (3,5) that is, x = 3 and y = 5 which means cost of 1 pencil is 3 and cost of 1 pen is 5.
  • 2 answers

Prince Kumar😁😁 3 years, 11 months ago

Do throw semple paper of Dapeeak

Dheeraj Joshi 3 years, 11 months ago

By your own mind ??
  • 1 answers

Shibi Maran 3 years, 11 months ago

Yes it's true.(They are similar in the ratio of thier areas as well as in sides i.e. 1:3 ratio)
  • 2 answers

[Vishal Kumar Paswan] [11] 3 years, 11 months ago

D = b²-4.a.c = 9801-508 = 9293 So , x = {-99(+-)√9293}/2 Ans.

Krishna Chaudhary 3 years, 11 months ago

127 ke LCM leke
  • 0 answers
  • 4 answers

Anshul Vishwakarma 3 years, 11 months ago

A =15

Naman Gupta 3 years, 11 months ago

A= 15°

Amar Singh 3 years, 11 months ago

A=15 °

Deepak Kumar 3 years, 11 months ago

A= 15°
  • 0 answers
  • 4 answers

[Vishal Kumar Paswan] [11] 3 years, 11 months ago

It is not possible for sinA to be greater than +1 ; ( -1<sinA<1 ) . So , the equation is incorrect .

[Vishal Kumar Paswan] [11] 3 years, 11 months ago

It is not possible for sinA to be greater than +1 ; ( -1<sinA<1 ) . Therefore , the equation is incorrect .

Abbas Ali Abidi 3 years, 11 months ago

Sin=P/H i.e. P=3 and H=1 Now,we have to find B=? By PGT (1)^2 - (3)^2 = (B)^2 1-9 = (B)^2 B= -√8 Since, Cos=B/H = -√8/1

Dhairya Sharma? 3 years, 11 months ago

Root of 8/1
  • 2 answers

[Vishal Kumar Paswan] [11] 3 years, 11 months ago

Here , D = b²-4.a.c = 36-(4.4.3) = -12 . Therefore , it has no real roots .

Adarsh Kumar 3 years, 11 months ago

11+6x
  • 1 answers

Deepak Kumar 3 years, 11 months ago

Question wrong hai..
  • 2 answers

Vikash Rana 3 years, 11 months ago

???diy

Suchitra Sen 3 years, 11 months ago

Maths *Polynomial Sum of zeros (alpha+beta)= -b/a Products of zeroes(alpha×beta)=c/a *Linear equations in two variable - if A1/a2=b1/b2=C1/C2 then in this condition graph will coincide nd will have infintly many solutions. -if A1/a2=b1/be€(not equal to)C1/c2 then grpah will become parallel line nd will have no solution. -if A1/a2 is not equal to b1/b2 then graph will intersect nd will have exactly one solution. * Areas related to circle -Area of circle=πr2 - Circumference of circle=2πr - Area of sector=thetha /360°×πr2 or - Area of sector= 1/2 × r × l - Area of segment=πr^2theta/360°-1/2r2sin thetha -Area of ring π(R2-r2)or π(R+r)(R-r) *Coordinate geometry - for a point PQ in graph PQ=√(x2-x1)^2+(y2-y1)^2 #Trignometry Sin = 1/cosec Cos =1/sec Tan=1/cot Tan = sin/ cos Cot=cos/sin *Identities Sine^2theta +cos^2thetha =1 Sorry if I have written any formula wrong ....nd hope it helps!!
  • 1 answers

Vikash Rana 3 years, 11 months ago

Theta is 60
  • 5 answers

Anshul Vishwakarma 3 years, 11 months ago

360

Tripti Rawat 3 years, 11 months ago

360

Aishveer Singh Ji 3 years, 11 months ago

360

Aishveer Singh Ji 3 years, 11 months ago

3y0

Adarsh Dubey 3 years, 11 months ago

360
  • 1 answers

Prince Tiwary 3 years, 11 months ago

7cosecA = 6 secA Therefore 7/6 = secA/cosecA Or sinA/cosA = 7/6 Or tanA = 7/6 Now draw a triangle with base = 6k and perpendicular = 7k apply Pythagoras theorem to get hypotenuse = (√85)k therefore sinA = 7k/(√85)k = 7/√85 therefore xsinA = 5 implies 7x/√85 = 5 therefore x = (5√85)/7

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