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tan 60 = h/BC
BC = h/{tex}\sqrt3{/tex} ....(1)
tan 30o = h/ BC+50
⇒ BC + 50 = {tex}\sqrt3{/tex}h
BC = {tex}\sqrt3{/tex}h − 50 ....(2)
From (1) & (2)
h{tex}\sqrt3{/tex} = {tex}\sqrt3{/tex}h − 50
⇒ h = 3h − 50{tex}\sqrt3{/tex}
⇒ 2h = 50{tex}\sqrt3{/tex}
⇒ h = 25{tex}\sqrt3{/tex}.
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Manish Routhan 3 years, 10 months ago
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