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Sia ? 3 years, 10 months ago
The sum of arithmetic progression whose first term is a and the common difference is d can be calculated using one of the following formulas: Sn = n/2 (2a+(n−1)d) and Sn = n/2 (a1+an). The sum of AP of n natural numbers is n(n+1)/2.
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Sia ? 3 years, 10 months ago
x2 + 6x + 9 = 0.
Put x = -3 in the equation
{tex}\Rightarrow{/tex}{tex}(-3)^2 + 6(-3) + 9{/tex}
{tex}\Rightarrow{/tex} {tex}9 - 18 + 9 =0{/tex}
Hence, it is a solution of the given equation.
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Rahul Pal 3 years, 9 months ago
1Thank You