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# A solution have 46% w/w ethylene …

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A solution have 46% w/w ethylene alochal (C2H5OH) in water find the mole fraction of ethyl alcohal

Tani Gupta 1 year, 2 months ago

Xb= 1/4, Xa=3/4

Arpit Agnihotri 1 year, 2 months ago

46%(w/w) C2H5OH = 46 gram of C2H5OH (solute) present in 100 gram of solution(solvent:water) mole fraction = (mole of solute)/ (mole of solute + mole of solvent) so, mole fraction of C2H5OH = [46/(2*12+6*1+1*16]/[{46/(2*12+6*1+1*16}+{54/2*1+1*16}] = [46/46]/[{46/46}+{54/18}] = 1/[1+3] = 1/4 hence, ans : mole fraction of C2H5OH = (1/4) molar mass of: C - 12; H - 1; O - 16 mole = mass / molar mass

Deepam Rawat 1 year, 2 months ago

.25 of ethylene gycocol

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