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In succesive measurment of periods of …

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In succesive measurment of periods of oscillation of pendulum,the reading turn out to be 2.63,2.56,2.42,2.71,2.80 seconds. Calculate absolute error,releative error and percentage error.

    • Posted by Saptarshi Roy 11 months, 3 weeks ago

    CBSE > Class 11 > Physics
    • 1 answers

    Barsha Kumbhakar 11 months, 3 weeks ago

    First calculate the arithmetic mean of readings, Xmean = X1 + X2 + X3 + X4 + X5 =(2.63+2.56+2.42+2.71+2.80)/5 = 2.62s The absolute error can be calculated as, For first reading, ΔX1=(2.63−2.62) ΔX1=0.01s For second reading, ΔX2=(2.56−2.62) ΔX2=0.06s For third reading, ΔX3=(2.42−2.62) ΔX3=0.20s For forth reading, ΔX4=(2.71−2.62) ΔX4=0.09s For fifth reading, ΔX5=(2.80−2.62) ΔX5=0.18s Calculate the arithmetic mean of absolute errors, ΔXmean=(ΔX1+ΔX2+ΔX3+ΔX4+ΔX5)/5 ΔXmean=(0.01+0.06+0.20+0.09+0.18)/5 ΔXmean=0.54/5 ΔXmean=0.11s Calculate the relative error, RE=ΔXmean/Xmean RE=0.11/2.62 RE=0.04s Calculate the percentage error, PE=(ΔXmean/Xmean)×100 PE=(0.11/2.62)×100 PE=4%

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