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Total number of atoms of all …

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Total number of atoms of all element present in one mole of ammonium dichromate is
  • 3 answers

Preeti Dabral 1 year ago

One molecule of ammonium dichromate,{tex}\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7{/tex}

contains 19 atoms.

Thus, one mole of ammonium dichromate will contain 19×6.02×1023=114×1023 atoms.

(nh4)2cr2o7 = (4+1)*2+2+7=19atoms , So that for one mole = 19*avagadro no. 19*6.023*10^23=114*10^23

Iva Jain 1 year ago

One molecule of ammonium dichromate, contains 19 atoms. Thus, one mole of ammonium dichromate will contain 19×6.02×1023=114×1023 atoms.
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