The adjacent angles of a parallelogram …
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Preeti Dabral 1 year, 1 month ago
Since, the adjacent angles of a parallelogram are supplementary.
{tex}\therefore{/tex} (2x - 4)° + (3x - 1)° = 180°
{tex}\Rightarrow{/tex} 5x - 5° = 180°
{tex}\Rightarrow{/tex} 5x = 185°
{tex}\Rightarrow{/tex} {tex}x=\frac{185^{\circ}}{5} \quad \Rightarrow \quad x=37^{\circ}{/tex}
Thus, the adjacent angles are
x = 37°
2x - 4 = 2 {tex}\times{/tex} 37°- 4 = 74 - 4 = 70°
and 3x -1 = 3 {tex}\times{/tex} 37 °- 1 = 111 - 1 = 110°
Hence, the angles are 70°, 110°, 70°, 110°
[{tex}\because{/tex} opposite angles in a parallelogram are equal]
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