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3x^3-6x^2+3x-7÷9 ÷ 3x-4

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3x^3-6x^2+3x-7÷9 ÷ 3x-4

    • Posted by Divyanshi Yadav 1 year, 2 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Asmi Chandila 1 year, 2 months ago

    P(x) = 3x³-6x²+3x-7/9 is divided by (3x-4). (3x-4)=0⇒x=4/3 .. the remainder = P(4/3) = 3(4/3) - 6(4/3)² + 3(4/3) - 7/9 =64/9-96/9 +4 - 7/9 =(64-96 +36-7)/9 = -1/3

    0Thank You

    Suyash Shubham 1 year, 2 months ago

    -59/9

    2Thank You

    ANSWER
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