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A uniform chain of length 2m …

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A uniform chain of length 2m is kept on a table such that a length of 60cm hangs freely from the edge of the edge of the table . The total mass of the chain is 4kg. What is the work done in pulling the entire chain on the table?
  • 1 answers

Mohit Sharma 6 years, 2 months ago

Givan
M and L are total lenght and mass of the chain.
M = 4 kg
L = 2 m


And let length and mass of part of chain hanging down are l and m respectively

l = 0.6 m


considering mass per unit length =>


M/L = m/l


m = l / L * 4 = (0.6 / 2) * 4 = 1.2 kg

Tension in chain hanging down = mg = 11.76 N (g=9.8 m/s^2)

Force required = Tension
Displacement = 0.6 m (part of chain hanging comes up)
W= Force * Displacement = 11.76 * 0.6 = 7.056 J
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