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12 ml of a gaseous hydro …

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12 ml of a gaseous hydro carbon was exploded with 50 ml of Oxygen . the volume measure after explosion was 32 ml . after treatment with KOH the volume demenesd to 8 ml . determine the formula of hydro carbon

Posted by Parnika Singh 1 year, 3 months ago

CBSE > Class 11 > Chemistry

1 answers

Shanika Sharma 1 year, 2 months ago

12 ml CxHy+50 ml(x+y/4)O2=xCO2+y/2 H2O ∴ volume of O2 (required to react with CxHy) =(x+y /4)volume of CxHy =(x+y/4)×12--------(1) After passing over KOH, CO2 is absorbed Then volume of O2 (remained) = 8 ml (2)⇒{50−12(x+y/4)}+12x=32 50−12x−3y+12x=32 50−3y=32⇒y= 50-32/3=6 (3)⇒50−12(x+y/4)=8 ⇒50−12x−3y=8 ⇒50−12x−18=8 ⇒2x=32−8 x=24/12=2 ∴ Hydrocarbon is C2H6 Note:- Volume of H2O is not taken because the volume measured at temp. below 1000C where it is liquid. However question doesn't specify it.

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