A right circular just encloses a …
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Preeti Dabral 1 year, 4 months ago
Radius of the base = r
Height = 2r
{tex}\therefore{/tex} Curved surface area of the cylinder = {tex}2\pi rh=2\pi (r)(2r)=4\pi r^2{/tex}
{tex}={{surface\ area\ of\ the\ sphere}\over{curved\ surface\ area\ of\ the\ cylinder}}{/tex}
{tex}={{4\pi r^2}\over{4\pi r^2}}={1\over1}=1:1{/tex}
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