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. A parallel plate air capacitor has a capacitance of 5uF . On introducing a conducting slab of thickness equal to one fourth of the distance between the plates , what would be increase in capacity ?

Posted by Ankit Kumar 1 year, 8 months ago

CBSE > Class 12 > Physics

2 answers

Adithya Dev 1 year, 7 months ago

What ??! No, no, no. It's not so negligible. It will have an effect, certainly. C = ε°A / (d - t + t/εr) = ε°A / (d - d/4 + d/4εr) = ε°A / (3d/4 - d/4εr).

0Thank You

Kalpesh Banjara 1 year, 8 months ago

No effect, because slab thickness will be negligible which doesn't effect capacitance

1Thank You

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