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# A compound contains 4.07% hydrogen 24.27% … ## CBSE, JEE, NEET, NDA

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A compound contains 4.07% hydrogen 24.27% carbon and 71.65%chlorine its molar mass is 98.96g what are its empirical and molecular formula ?

Tanushree Mukherjee 2 weeks, 3 days ago

Hydrogen — 4.07% Carbon–24.27% Chlorine—71.65% Molar Mass Is 98.96G To Calculate Empirical Formulae, first, we have to divide the given percentages of atoms by their molecular masses. Hydrogen — 4.07 / 1 = 4.07 Carbon–24.27 / 12 = 2.02 Chlorine—71.65 / 35.5 = 2.01 Now we have to divide all the values with the lowest obtained value. Hydrogen — 4.07 / 2.01 = 2 Carbon–2.02 / 2.01 = 1 Chlorine— 2.01 / 2.01 = 1 Therefore, the empirical formula is CH2Cl To Calculate Molecular Formulae, we need to find the weight of the empirical formula CH2Cl 12 + 2*1 + 35.5 = 49.5 The molecular weight- 98.96 is double of empirical weight. Therefore molecular formula is C2H4Cl2

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