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A solid spherical conductor of radius …

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A solid spherical conductor of radius R has a spherical cavity of radius a ( a< R) at it's centre.A charge+Q is kept at the centre. The charge at the inner surface,outer and at a position r ( a<r<R ) are respectively

Posted by Lakshmi M 1 year, 9 months ago

CBSE > Class 12 > Physics

2 answers

★ 1 year, 9 months ago

<font face ="Times New Roman">At r < a, 0 . As there is only field there.

0Thank You

★ 1 year, 9 months ago

<font face ="Times New Roman">Inner surface = -Q
Outer surface = +Q
At r<a, 0, as there is only field

0Thank You

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CBSE > Class 12 > Physics