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The resistance of 10 -2M NaCl …

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The resistance of 10 -2M NaCl in a conductivity cell solution is found to be 210 Ω. The specific conductance of this solution is 4.5 x 10 -3 S/cm. Calculate the cell constant.

Posted by Atiya Shahab 2 years, 2 months ago

CBSE > Class 12 > Chemistry

1 answers

Mr. Singh 2 years, 2 months ago

Solution Verified by Toppr R=210Ω N=0.01N x=Al=0.88cm−1 k=c.x=(2101×0.88)Ω−1cm−1=conductivity=4.19×10−3 Λeq=(k×N1000)=(2101×0.010.88×1000)=419.04Scm2eq−1

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CBSE > Class 12 > Chemistry