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Evaluate: $$\displaystyle \int \dfrac{1}{cos(x-a)cos(x-b)}dx$$

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Evaluate: $$\displaystyle \int \dfrac{1}{cos(x-a)cos(x-b)}dx$$
  • 2 answers

Harshit Singh 4 months ago

Both num. Deno. Multiply by sin(b-a)

Atharva Verma 4 months, 3 weeks ago

1/sin(a-b)log cos (x-a)/cos(x-b)+C
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