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Evaluate: $$\displaystyle \int \dfrac{1}{cos(x-a)cos(x-b)}dx$$

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Evaluate: $$\displaystyle \int \dfrac{1}{cos(x-a)cos(x-b)}dx$$

Posted by ★ 2 years, 3 months ago

CBSE > Class 12 > Mathematics

5 answers

★ 1 year, 10 months ago

<font face = "Courier New">for i in rabge shshsj

★ 1 year, 10 months ago

$$\displaystyle \lim_{x \to 1}\left[\dfrac{a + sin(x-1) - ax}{x + sin(x-1) - 1}\right]^{\dfrac{1-x}{1-\sqrt{x}}} = \dfrac{1}{4}$$

★ 1 year, 10 months ago

$$\lim_{x \to 1} \left[\dfrac{a + sin(x-1) - ax}{x + sin(x-1) - 1}\right]^{\dfrac{1-x}{1-\sqrtx}} = \dfrac{1}{4}$$

Harshit Singh 2 years, 2 months ago

Both num. Deno. Multiply by sin(b-a)

Atharva Verma 2 years, 3 months ago

1/sin(a-b)log cos (x-a)/cos(x-b)+C

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