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Y=loglogx×x then find dy÷dx

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Y=loglogx×x then find dy÷dx
  • 1 answers

Ashwini M 3 months, 1 week ago

dy/dx = x (1/logx) ×1/x +log logx = (1/logx) +log logx
http://mycbseguide.com/examin8/

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