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The equilibrium constant for the reaction …

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The equilibrium constant for the reaction SO3 (g) ⇌ SO2 (g) + 12 O2 (g) is 0.18 at 900 K. What will be the equilibrium constant for the reaction SO2 (g) + 12 O2 (g) ⇌ SO3 (g)?

    • Posted by Anshu Dudi 2 years, 4 months ago

    CBSE > Class 11 > Chemistry
    • 2 answers

    Shobhit Kumar 2 years, 4 months ago

    For the reverse rax", equilibrium constant become 1/k So 1/0.18=5.6

    0Thank You

    Mohd Daud 2 years, 4 months ago

    For the reverse reaction, equilibrium constant becomes 1/k , So 1/0.18= 5.55

    1Thank You

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