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solve the following pair of linear equations. (I)ax+by=a-b,bx-ay=a+b

Preeti Dabral 1 month, 1 week ago

ax+by=a-b
ax=a-b-by
x=a-b-by/a←

bx-ay=a+b
substituting
b(a-b-by/a)-ay=a+b
ab-b²-b²y/a-ay=a+b
ab-b²-b²y-a²y/a=a+b
ab-b²-(b²+a²)y=a²+ab
-(b²+a²)y=a²+ab-ab+b²
(b²+a²)y=-(a²+b²)
y=-(a²+b²)/a²+b²
y=-1←

substituting value of y
x=a-b-b(-1)/a
x=a-b+b/a
x=a/a
x=1

Bhawna Yadav 1 month, 1 week ago

ax+by=a-b ax=a-b-by x=a-b-by/a← bx-ay=a+b substituting b(a-b-by/a)-ay=a+b ab-b²-b²y/a-ay=a+b ab-b²-b²y-a²y/a=a+b ab-b²-(b²+a²)y=a²+ab -(b²+a²)y=a²+ab-ab+b² (b²+a²)y=-(a²+b²) y=-(a²+b²)/a²+b² y=-1← substituting value of y x=a-b-b(-1)/a x=a-b+b/a x=a/a x=1

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