A scooter was bought at ₹42000. …
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Sia ? 2 years, 6 months ago
P = ₹ 42000
R = 8% per annum
n = 1 year
{tex}\therefore{/tex} {tex}A = P{\left( {1 - \frac{R}{{100}}} \right)^n}{/tex}
{tex} = 42000{\left( {1 - \frac{8}{{100}}} \right)^1}{/tex}
{tex} = 42000\left( {1 - \frac{2}{{25}}} \right){/tex}
{tex} = 42000 \times \frac{{23}}{{25}}{/tex}
= ₹ 38640
Hence, its value after 1 year is ₹ 38640.
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