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A and B Two train length …

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A and B Two train length 400m traveling two parallel track with uniform speed of 72km/h .The driver of train B decide to overtake train A and accelerate by 1m/s upon 2. After 50s the guard of B just bushed passed the driver of A. Then what was the original distance between them
  • 1 answers

Preeti Dabral 2 years, 9 months ago

For train A:
Initial velocity, u = 72 km/h = 20 m/s
Time, t = 50 s
Acceleration, aI = 0 (Since it is moving with a uniform velocity)
From second equation of motion, distance (SI) covered by train A can be obtained as:
{tex}s _ { I } = u t + \frac { 1 } { 2 } a _ { I } t ^ { 2 }{/tex}
= 20 {tex}\times{/tex} 50 + 0 = 1000 m
For train B:
Initial velocity, u = 72 km/h = 20 m/s
Acceleration, a = 1 m/s2
Time, t = 50 s
From second equation of motion, distance (SII) covered by train A can be obtained as:
{tex}s _ { II } = u t + \frac { 1 } { 2 } a t ^ { 2 }{/tex}
{tex}= 20 \times 50 + \frac { 1 } { 2 } \times 1 \times ( 50 ) ^ { 2 } = 2250 \mathrm { m }{/tex}
Length of both trains = 2 {tex}\times{/tex} 400 m = 800 m
Hence, the original distance between the driver of train A and the guard of train B is 2250 - 1000 - 800 = 450 m.

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