A bag contains 6 white and 5 red balls. Another bag contain 5 white and 8 red balls . A ball is transfered from bag 1 to bag 2 and then a ball is drawn from second bag . Find the probability that the ball drawn from the second bag is red in colour

Posted by .Aks Kumar Singh Daksh Prajapati 1 month ago

- 5 answers

.Aks Kumar Singh Daksh Prajapati 4 weeks ago

Required prob =P(a white ball is transfered ) + P(a red ball is transfered) = 6/11×8/14 + 5/11×9/14 = 93/154

Anish Pandey 4 weeks, 1 day ago

A= ball drawn from 2nd bag
Ei= ball transferred to 2nd bag was red
Ej= ball transferred to 2nd bag was white
Now,
By theorem of total probability we have,
P(A)= P(Ei) P(A/Ei) +P(Ej) P(A/Ej)
P(Ei)= 5/11
P(Ej)= 6/11
P(A/Ei)= 9/14
P(A/Ej)= 8/14
P(A)= 5/11×9/14 + 6/11×8/14
P(A)= 93/11

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.Aks Kumar Singh Daksh Prajapati 4 weeks ago

0Thank You