T the base of an isosceles …
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Posted by Jazim Javaid 3 years, 4 months ago
- 2 answers
Gaurav Seth 3 years, 4 months ago
Let the length of equal sides be x cm.
Perimeter = x cm + x cm + Base = 4 2/15 cm
2x + 4/3 = 62/15
On transposing 4/3 to R.H.S, we obtain
2x = 62/15 - 4/3
2x = 62 - 4 x 5/15 = 62 - 20/15
2x = 42/15
On dividing both sides by 2, we obtain
2x/2 = 42/15 x1/2
x = 7/5 = 1 2/5
Therefore, the length of equal sides is 1 2/5 c m.
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Sudheer Vishawkama 3 years, 3 months ago
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