Prove that in a triangle other …
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Yogita Ingle 3 years, 8 months ago
Given -- ΔABC other than equilateral triangle.
The construction is already given in the picture.So let me just establish the relation between the sides.
Let AB = AD = DB
ABD is an equilateral triangle since AB = AD = DB
∠ABD = ∠ADB = ∠BAD = 60°
Longest side= BC
Angle opposite to longest side = ∠BAC
Here it is clear that ∠BAC = ∠BAD + ∠CAD
So ∠BAC > ∠BAD
∠BAC > 60°
2/3 of right angle = 2/3 × 90 = 60
SO,
angle(BAC) > 2/3 of right angle
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