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Let ABCD be a Trapezium in …

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Let ABCD be a Trapezium in which AB is parallel to CD. AB =11 ,BC = 4, CD = 6 and DA= 3. Find the distance between AB and CD.

  • 1 answers

Govind Singh 6 years, 3 months ago

Let ABCD is the trapezium and h is the height which is required to be found.

Let AB=11 cm, CD=6 cm and AB is parellel to CD.

Let distance between foot of perpendicular h and A is X.

So distance between B and foot of 2nd perpendicular from C=11–6-x=5-x.

There are 2 rt. angled triangles.

Applying Pythogorous theorem,

For one triangle,

h^2=3^2-x^2 .........(1)

For 2nd triangle,

h^2=4^2-(5-x)^2 ........(2)

From (1)&(2), x=1.8 cm and

required h=2.4 cm

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