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calculate the force of attraction exerted by the nucleus of hydrogen atom on the electron revolving in its first orbit given radius of first orbit of hydrogen atom is .529 angstrom

Posted by Ravina Nain 3 years, 10 months ago

CBSE > Class 12 > Physics

1 answers

Priti Dubey 3 years, 10 months ago

Radius equal to 0.59 angstrom so 1 angstrom equal to 10 to the power minus 10 so new radius would be in metre that is 0.529 into 10 to the power minus 10 now we know that you means charge of an electron equal to 1.6 into 10 to the power minus 19 in negative sign whereas charge on a Proton which is in positive sign 1.6 into 10 to the power minus 19 as well flow from coulombs law we know that f is equal to q e n to q p upon R square now we get the final answer which is 60.4 Newton

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CBSE > Class 12 > Physics