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How many atoms are present in …

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How many atoms are present in 16 gram of ozone
  • 1 answers

Yogita Ingle 4 years ago

Molar mass of O3 will be 16 x3 =48 g .

Here 16g 0f O3 is given so no of moles of O3 will be 16 ÷48 = 1/3 mole .

now 1 mole = 3 ×6.022 ×{10^23} oxygen atoms therefore 1/3 mole =6.022 ×1/3×3 ×{10 ^23} no of atoms.

O3 is Ozone molecule which contain 3 Oxygen atoms.

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