Sodium carbonate reacts with ethanoic acid …
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Sodium carbonate reacts with ethanoic acid to form sodium ethanoate, carbon dioxide
and water. In the experiment, 5.3g of sodium carbonate reacted with 6g of ethanoic acid to
form 8.2g of sodium ethanoate, 2.2g of carbon dioxide and 0.9g of water. Show that this data
verifies the law of conservation of mass.
Posted by Jo Tesh 4 years, 1 month ago
- 1 answers
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Yogita Ingle 4 years, 1 month ago
Mass of sodium carbonate = 5.3 g (given)
Mass of ethanoic acid = 6 g (given)
Mass of sodium ethanoate = 8.2 g (given)
Mass of Carbon dioxide = 2.2 g (given)
Mass of water = 0.9 g (given)
Now, total mass before the reaction = (5.3 + 6) g
= 11 . 3 g
And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g
= 11.3 g
total mass before the reaction = total mass after the reaction.
Hence, the given observations are in agreement with the law of conservation of mass.
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