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Prove : [cos3x+2cos5x+cos7x]/[cosx+2cos3x+cos5x] = cos2x - …

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Prove : [cos3x+2cos5x+cos7x]/[cosx+2cos3x+cos5x] = cos2x - sin2x.tan3x
  • 1 answers

Rahul Poddar 6 years, 5 months ago

(cos7x+cos3x)+2cos5x/(cos5x+cosx)+2cos3x. ........2cos5xcosx+2cos5x/2cos3xcos2x+2cos3x.......2cos5x (cos2x+1)/2cos3x (cos2x+1)....cos5x/cos3x.....cos (3x+2x)/cos3x......cos3xcos2x-sin3xsin2x/cos3x.. cos3xcos2x/cos3x-sin3xsin2x/cos3x.... cos3x-sin3xsin2x. .....solved
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