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(sina+cosa)^2=1+2sina×cosa

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(sina+cosa)^2=1+2sina×cosa
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Abhijeet Singh 6 years, 6 months ago

By using identity (a+b)^2= a^2 + b^2 + 2ab Therefore, LHS, = (SinA +CosA)^2 = Sin^2A + Cos^2A + 2SinACosA = 1 + 2SinACosA [ Sin^2 + Cos^2A =1] PROVED
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