No products in the cart.

In an A. P 8,11,14,... Find …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

In an A. P 8,11,14,... Find Sn-Sn-1
  • 2 answers

Poshika Dhir 4 years, 5 months ago

In this AP a=8and d=11-8=3 Sn=n/2[2a+(n-1)d] =n/2[2x8+(n-1)3] =n/2 [16+(n-1)3] Replace n by n-1 Sn-1=n-1/2[2x8+(n-1-1)3] =n-1/2[16+(n-2)3] Now Sn-Sn-1=n/2[16+(n-1)3]-n-1/2[+(n-2)3] Now on solving you will get the answer hope it will help you thanks

Chiru Yavvari 4 years, 5 months ago

Vnnk
http://mycbseguide.com/examin8/

Related Questions

Solve cos2x -5sinx -3=0
  • 0 answers
What is sin60
  • 4 answers
Option of photo
  • 0 answers
Derivative of cube root of tanx
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App