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A batsman hits back a ball …

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A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12m/s. If the mass of the ball is 0.15kg, determine the impulse imparted to the ball.
  • 2 answers

Raina Ahlawat 4 years, 7 months ago

Here u=12m/sec V= -12m/sec M= 0.15kg J= m(v-u) =0.15(-12-12) = -3.6 N sec

Sia ? 4 years, 7 months ago

Impulse = change in linear momentum .
initial momentum of ball= mu
=0.15 {tex}\times{/tex}12 =1.8 kg.m/sec

final momentum of ball = -mu
= - 0.15 {tex}\times{/tex} 12 = -1.8 kgm/sec

now,
change in momentum of ball =final -initial
= -1.8 -1.8 = -3.6 kgm/sec
so,
change in momentum of bat = -change in momentum of ball
change in momentum of bat =3.6 kgm/s
now,
impulse imparted to ball =change in momentum of bat = 3.6 kgm/s

 

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