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Anyone Help ???plz...Integrate :- 1/x(log x)^m …

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Anyone Help ???plz...Integrate :- 1/x(log x)^m .....where x>0 , m not equal to 1...

Posted by Aman Kumar 4 years, 8 months ago

CBSE > Class 12 > Mathematics

3 answers

Aman Kumar 4 years, 7 months ago

Ans :- (log x)^1-m/ 1-m + C

Miss Mor 4 years, 7 months ago

Ans. Logx^m+1/m+1 +c Solution. Put log x=t dx=dt.x Integration 1/x.t^m.dt.x Integration t^m.dt =t^m+1/m+1 +c =logx^m+1/m+1 +c

Khuskaran Sidhu 4 years, 7 months ago

Put log x =t Now, derivate => (1/x )dx =dt Now, In t dt => t^2/2 +C Ans.

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