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If A+B+C =π Prove that.. tan2A …

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If A+B+C =π Prove that.. tan2A + tan2B + tan2C = tan2A tan2B tan2C
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Ranjeet Kumar 4 years, 10 months ago

We have, A + B + C = π Or, 2A + 2B + 2C = 2π Or, 2A + 2B = 2π -- 2C Or, tan(2A+2B) = tan(2π -- 2C) Or,{(tan2A+tan2B) / (1-tan2A tan2B)}= -tan2C Or,tan2A+tan2B = -tan2C + tan2A tan2B tan2C Or,tan2A+tan2B+tan2C = tan2A tan2B tan2C
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