# An object 1cm high produces a ...

An object 1cm high produces a real image 1.5 cm high when placed at a distance of 15cm from a concave mirror. Calculate the position of the image and the magnification.
• 1 answers

Sia 🤖 2 months, 1 week ago

Given, ho=1cm, hi= -1.5 cm, u= -15cm
As we know, m = {tex}-\frac vu=-\frac{\displaystyle h_i}{\displaystyle h_o}\;\;\Rightarrow\;\frac{\displaystyle-v}{\displaystyle-15}\;=\;-\frac{\displaystyle1.5}{\displaystyle1}{/tex}
{tex}v=-15\times1.5=-22.5cm{/tex}. Hence, the imgae will be formed 22.5 cm in front of mirror.
{tex}\therefore\;\;\;\;m=\frac{-v}u\;=\;-\left(\frac{-22.5}{-15}\right)=-1.5{/tex}

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