A man invests Rupees 2000 in …
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Naveen Sharma 6 years, 10 months ago
Ans. His saving will form an AP
First term of AP (a) = 2000
Common Difference (d) = 100 (as he increased amount by 100)
No of Months (n) = 2 years = 2 * 12 = 24 months
Total Money = {tex}{n\over 2} [2a+(n-1)d]{/tex}
= {tex}{24\over 2}[2\times 2000 + (24-1)\times 100]{/tex}
=> {tex}12 [4000 + 2300]{/tex}
=> 12 [6300]
= 75600
He ll have Rs 75600 at the end of 2 years.
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