Show that f(x)=|x|+2 is not onto
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Posted by Simran Srikoti 4 years, 10 months ago
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Sia ? 4 years, 10 months ago
Modulus Function f : R {tex}\rightarrow{/tex} R, given by f(x) = |x| + 2
One-one: f(1) = |1| + 2 = 3 and f(2) = |2| + 2 = 4,so distinct elements have same image.So, f is not one-one.
Onto: f takes only positive values, so range(f) = set of positive real numbers {tex}\neq{/tex} R, codomain. So, f is not onto.
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