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4 gm of carbon is heated …

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4 gm of carbon is heated with 8 gm of sulphur .how much cs2 will be formed when the reaction is complete . What will be the % purity?

A 70.2%

B 79.2%

C 90%

D 90.2%

  • 1 answers

Payal Singh 6 years, 10 months ago

B. 79.2% 

{tex}C + 2S \to CS_2{/tex}

Ideally, 1 mole of C will react with 2 moles of S to form CS2 

1 mol of C = 12g 1 mol of S = 32g

12g carbon reacts with = 64g of Sulphur 1g carbon reacts with = {tex}64\over 12{/tex}g of Sulphur

4g carbon reacts with = {tex}{64\over 12}\times 4 = {64\over 3}{/tex}g of Sulphur

But we have only 8g of sulphur

It mean sulphur is limiting agent.

due to sulphur is limiting reagent reaction will proceed according to sulphur .

64g sulphur formed = 76g CS2

1g S formed=  {tex}76\over 64{/tex} g CS2

8g S formed = {tex}{76\over 64 }\times 8 = 9.5{/tex}g CS2

Hence, % purity {tex}= {Wt. \ of \ product \over Wt. \ of \ reactants } \times 100{/tex}{tex} {9.5 \over (4+8)}\times 100 ={ 9.5\over 12}\times 100 {/tex}

= 79.16 % = 79.2 %

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