4 gm of carbon is heated …
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Payal Singh 6 years, 10 months ago
B. 79.2%
{tex}C + 2S \to CS_2{/tex}
Ideally, 1 mole of C will react with 2 moles of S to form CS2
1 mol of C = 12g 1 mol of S = 32g
12g carbon reacts with = 64g of Sulphur 1g carbon reacts with = {tex}64\over 12{/tex}g of Sulphur
4g carbon reacts with = {tex}{64\over 12}\times 4 = {64\over 3}{/tex}g of Sulphur
But we have only 8g of sulphur
It mean sulphur is limiting agent.
due to sulphur is limiting reagent reaction will proceed according to sulphur .
64g sulphur formed = 76g CS2
1g S formed= {tex}76\over 64{/tex} g CS2
8g S formed = {tex}{76\over 64 }\times 8 = 9.5{/tex}g CS2
Hence, % purity {tex}= {Wt. \ of \ product \over Wt. \ of \ reactants } \times 100{/tex} = {tex} {9.5 \over (4+8)}\times 100 ={ 9.5\over 12}\times 100 {/tex}
= 79.16 % = 79.2 %
0Thank You