Find the value of 'a' so …
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Posted by Mukund Rangwani 4 years, 7 months ago
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Sia ? 4 years, 7 months ago
Since the point (3, a) lies on the line 2x - 3y = 5, we have
2 {tex}\times{/tex} 3 - 3 {tex}\times{/tex} a = 5
{tex}\Rightarrow{/tex} 6 - 3a = 5
{tex}\Rightarrow{/tex} 3a = 1
{tex}\Rightarrow{/tex} {tex}a = \frac { 1 } { 3 }{/tex}
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