The freezing point depression of .001 …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Chandgiram Chandgi 3 years, 8 months ago
- 0 answers
Posted by Md Arif 3 years, 5 months ago
- 1 answers
Posted by Vivek Choudhary 3 years, 3 months ago
- 1 answers
Posted by Diksha Singh 2 months ago
- 0 answers
Posted by Panav Srivastava 2 years, 10 months ago
- 1 answers
Posted by Kundan Kumar 3 years, 3 months ago
- 1 answers
Posted by Punam Kumari 3 years, 6 months ago
- 1 answers
Posted by Seema M K 2 years, 2 months ago
- 2 answers
Posted by Muskan Singh 3 years, 6 months ago
- 1 answers
Posted by Roshni Kumari 2 years, 7 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 5 years ago
Freezing point depressionΔTf = i × Kf × mi = ΔTf Kf × m = 7.10 × 10−31.86 × 0.001 =3.82 ≈ 4The total number of value of i = 4The given complex Kx[Fe(CN)6] has already complex ion [Fe(CN)6] as 1.So the remaining are K ions = 4−1 = 3Thus the value of x =3 and the complex is K3[Fe(CN)6]
1Thank You