In a 3-digit no. Unit's digit, …
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Amar Kumar 6 years, 6 months ago
Let the common multiple be x
As per question the ratio is 1:2:3
so the required no. be 300x+20x+x
On reversing the digits the no. would be 100x+20x+3x
300x+20x+x-( 100x+20x+3x)=594
300x+20x+x- 100x-20x-3x=594
200x-2x=594
x=3
so the required no. be 300x+20x+x= 900+60+3
=963
To check
963-369=594
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