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Find square root of -15-8i

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Find square root of -15-8i

Posted by Raghav Sharma 5 years, 1 month ago

CBSE > Class 11 > Mathematics

1 answers

Mohit Shrivastav 5 years, 1 month ago

Let the sq. root of √ -15-8i=+-(x+iy) On Sq. both sides we get, -15-8i=x^2+(yi)^2+2xyi -15-8i=^2-y^2+2xyi (i^2=-1) on comparing, we get, =x^2-y^2=-15 ........(1) 2xy=8 We know that (x^2+y^2)^2=(x^2-y^2)^2+(2xy) ^2 On putting the values, we get (x^2+y^2)^2=(-15)^2+(8)^2=279 (x^2+y^2)=17 .........(2) On solving (1)and(2),we get X=+-(1),y=+-(4) Hence, √-15-8i=+-(1+4i)

2Thank You

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CBSE > Class 11 > Mathematics