Two cross roads each of width …
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Posted by Surinder Singh 3 years, 11 months ago
- 2 answers
Gaurav Seth 5 years ago
Here, PQ = 10 m and PS = 300 m, EH = 10 m and EF = 700 m And KL = 10 m and KN = 10 m
Area of roads
= Area of PQRS + Area of EFGH – Area of KLMN
[∵ KLMN is taken twice, which is to be subtracted]
= PS x PQ + EF x EH – KL x KN
= (300 x 10) + (700 x 10) – (10 x 10)
= 3000 + 7000 – 100
= 9,900 m2
Area of road in hectares,
1 m2 =1/10000 hectares
9,900 m2 =9900/10000
= 0.99 hectares
Now, Area of park excluding cross roads = Area of park – Area of road = (AB x AD) – 9,900
= (700 x 300) – 9,900
= 2,10,000 – 9,900
= 2,00,100 m2
= 200100 hectares = 20.01 hectares
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Prashant Bhati 5 years ago
1Thank You