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Derivation of potential energy

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Derivation of potential energy
  • 2 answers

Drishti Tandon 5 years, 2 months ago

We know that w=f*s Work is equal to potential energy According to newton's second law of motion, f=m*a So in w=f*s P.E. = m*a*s We know that a=g So, P.E. = m*g*s s=h (distance covered) This concludes that P.E. = m*g*h

Sudhir Rathi 5 years, 2 months ago

W=force ×displacement mg×h W=mgh PE=mgh
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