Find the area of the parallelogram …
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Posted by Gaurav Singh 5 years, 3 months ago
- 2 answers
Yogita Ingle 5 years, 3 months ago
If AC is diagonal and ABCD is a parallelogrm
Semi-perimeter of triangle ABC = a+b+c/2
14+15+13/2 = 21 cm
Area of triangle ABC = √S(S-A)(S-B)(S-C)
= √[21(21-14)(21-15)(21-13)
= √21 (7)(6) (8)
=7056 cm square
Semi-perimeter of triangle BDC= a+b+c/2
14+15+13/2 = 21 cm
Area of triangle BDC = √S(S-A)(S-B)(S-C)
= √[21(21-14)(21-15)(21-13)
=7056 cm square
Area of paralleiogram = area of triangle ABC + area of triangle BDC
= 7056+7056
=14112cm square
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Gaurav Singh 5 years, 3 months ago
3Thank You