Write one factor of (x+1)cube -(x+1)
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Posted by Shalu Shalini 5 years, 2 months ago
- 1 answers
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Yogita Ingle 5 years, 2 months ago
(x+1)3 - (x+1)
= (x+1) (x+1)2 - (x +1)
= (x + 1) [(x + 1)2 - 1]
= (x + 1)[x2 + 2x +1 -1]
= (x + 1) (x2 + 2x]
= x (x + 1) (x + 2)
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